619 98th Ave
Tisdale, Saskatchewan, S0E1T0, Canada
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Approx. price(Jan 2020):
$89,000
| Building type: | House |
| Building style: | Bungalow |
| Land Size: | 50x120 |
| Floor Space: | 900 sqft |
| Bathrooms: | 1 |
| Bedrooms: | 3 |
| Parking Type: | Detached garage, Interlocked, Parking Sp |
| Heating Type / Fuel: | Forced air |
Property Description
House for sale in Tisdale located in 619 98th Ave , Saskatchewan, S0E1T0, Canada. This House have 3 bedrooms and 1 bathrooms. This property listing building style is Bungalow. For all the rest of the information we have about this property in Tisdale , see above.
900 sqft bungalow with a 864 sqft basement, 3 bedrooms and a 4 piece bath on the main. Big living room as well as a kitchen/dining room combo. The basement is unfinished, but started. 100 amp panel box. Updated windows and siding. There is a 24x24 detached garage with concrete and power with back alley access. This property will need some major TLC and is being sold ''AS IS'', there are no warranties or representations as to the function ability. Gas line encroachment exists. Schedule ''A'' must accompany any and all offers.
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619 98th Ave, Tisdale, Saskatchewan, S0E1T0, Canada
